The volume of an air bubble become three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg an density of water to be 1/10 of the density of mercury, the depth of the lake is
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Verified by ExpertsThe correct answer is:
C
P 1 V 1 = P 2 V 2 ⇒ (P0 + h ρ g) V = P 0 × 3V
h ρ g = 2P 0 ⇒ h = 
=15m
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